mi: Remove semi-arbitrary arch awareness in packed coordinate macros
The majority of arches end up on the right-shift path here. I can't think of any arch where that'd be slower than a divide, and semantically it makes more sense to think of this as a shift operation anyway. Signed-off-by: Adam Jackson <ajax@redhat.com> Reviewed-by: Keith Packard <keithp@keithp.com> Signed-off-by: Keith Packard <keithp@keithp.com>
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mi/micoord.h
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mi/micoord.h
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@ -32,27 +32,7 @@
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/* Macros which handle a coordinate in a single register */
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/*
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* Most compilers will convert divisions by 65536 into shifts, if signed
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* shifts exist. If your machine does arithmetic shifts and your compiler
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* can't get it right, add to this line.
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*/
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/*
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* mips compiler - what a joke - it CSEs the 65536 constant into a reg
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* forcing as to use div instead of shift. Let's be explicit.
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*/
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#if defined(mips) || \
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defined(sparc) || defined(__sparc64__) || \
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defined(__alpha) || defined(__alpha__) || \
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defined(__i386__) || defined(__i386) || defined(__ia64__) || \
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defined(__s390x__) || defined(__s390__) || \
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defined(__amd64__) || defined(amd64) || defined(__amd64)
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#define GetHighWord(x) (((int) (x)) >> 16)
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#else
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#define GetHighWord(x) (((int) (x)) / 65536)
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#endif
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#if IMAGE_BYTE_ORDER == MSBFirst
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#define intToCoord(i,x,y) (((x) = GetHighWord(i)), ((y) = (int) ((short) (i))))
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