Disable new signal-based asynchronous goroutine preemption from GO 1.14 in git env (#11237)

As seen in trouble shooting #11032 the new feature of Go 1.14 is causing several second delays in startup in certain situations. Debugging shows it spending several seconds handling SIGURG commands during init:

```
6922:04:51.984234 trace init() ./modules/queue/unique_queue_wrapped.go
remote: ) = 69 <0.000012>
remote: [pid 15984] 22:04:51 write(1, "\ttime taken: 236.761\302\265s\n\n", 25    time taken: 236.761µs
remote:
remote: ) = 25 <0.000011>
remote: [pid 15984] 22:04:51 --- SIGURG {si_signo=SIGURG, si_code=SI_TKILL, si_pid=15984, si_uid=0} ---
remote: [pid 15984] 22:04:52 --- SIGURG {si_signo=SIGURG, si_code=SI_TKILL, si_pid=15984, si_uid=0} ---
remote: [pid 15984] 22:04:52 --- SIGURG {si_signo=SIGURG, si_code=SI_TKILL, si_pid=15984, si_uid=0} ---
```

This causes up to 20 seconds added to a push in some cases as it happens for each call of the gitea hook command. This is likely the cause of #10661 as well and would start to effect users once we release 1.12 which would be the first release compiled with Go 1.14. I suspect this is just a slight issue with the upstream implementatation as there have been a few very similar bugs fixed and reported:

 https://github.com/golang/go/issues/37741
 https://github.com/golang/go/issues/37942

We should revisit this in the future and see if a newer version of Go has solved it, but for now disable this option in the environment that gitea hook runs in to avoid it.
This commit is contained in:
mrsdizzie 2020-04-28 11:45:32 -04:00 committed by GitHub
parent 1f0b797ddc
commit 922a239079
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@ -119,6 +119,8 @@ func (c *Command) RunInDirTimeoutEnvFullPipelineFunc(env []string, timeout time.
cmd.Env = env cmd.Env = env
cmd.Env = append(cmd.Env, fmt.Sprintf("LC_ALL=%s", DefaultLocale)) cmd.Env = append(cmd.Env, fmt.Sprintf("LC_ALL=%s", DefaultLocale))
} }
cmd.Env = append(cmd.Env, "GODEBUG=asyncpreemptoff=1")
cmd.Dir = dir cmd.Dir = dir
cmd.Stdout = stdout cmd.Stdout = stdout
cmd.Stderr = stderr cmd.Stderr = stderr