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[utils] Support TTML without default namespace
In a strict sense such TTML is invalid, but Yahoo uses it.
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@ -621,6 +621,21 @@ def test_dfxp2srt(self):
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'''
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self.assertEqual(dfxp2srt(dfxp_data), srt_data)
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dfxp_data_no_default_namespace = '''<?xml version="1.0" encoding="UTF-8"?>
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<tt xml:lang="en" xmlns:tts="http://www.w3.org/ns/ttml#parameter">
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<body>
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<div xml:lang="en">
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<p begin="0" end="1">The first line</p>
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</div>
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</body>
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</tt>'''
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srt_data = '''1
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00:00:00,000 --> 00:00:01,000
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The first line
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'''
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self.assertEqual(dfxp2srt(dfxp_data_no_default_namespace), srt_data)
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if __name__ == '__main__':
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unittest.main()
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@ -1848,9 +1848,9 @@ def parse_node(node):
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out = str_or_empty(node.text)
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for child in node:
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if child.tag == _x('ttml:br'):
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if child.tag in (_x('ttml:br'), 'br'):
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out += '\n' + str_or_empty(child.tail)
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elif child.tag == _x('ttml:span'):
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elif child.tag in (_x('ttml:span'), 'span'):
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out += str_or_empty(parse_node(child))
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else:
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out += str_or_empty(xml.etree.ElementTree.tostring(child))
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@ -1859,7 +1859,10 @@ def parse_node(node):
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dfxp = xml.etree.ElementTree.fromstring(dfxp_data.encode('utf-8'))
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out = []
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paras = dfxp.findall(_x('.//ttml:p'))
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paras = dfxp.findall(_x('.//ttml:p')) or dfxp.findall('.//p')
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if not paras:
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raise ValueError('Invalid dfxp/TTML subtitle')
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for para, index in zip(paras, itertools.count(1)):
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begin_time = parse_dfxp_time_expr(para.attrib['begin'])
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