Adrian Gonzalez baac352f74 WebSocketClientHandshaker.rawPath(URI) should use the raw query ... Motivation: If the wsURL contains an encoded query, it will be decoded when generating the raw path. For example if the wsURL is http://test.org/path?a=1%3A5, the returned raw path would be /path?a=1:5 Modifications: Use wsURL.getRawQuery() rather than wsURL.getQuery() Result: rawPath will now return /path?a=1%3A5		2016-11-14 08:45:27 +01:00
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src	WebSocketClientHandshaker.rawPath(URI) should use the raw query	2016-11-14 08:45:27 +01:00
pom.xml	[maven-release-plugin] prepare for next development iteration	2016-10-14 13:20:41 +02:00