c663a94359
Motivation: We need to release all the buffers that may be put into our inbound queue since we closed the Channel to ensure we not leak any memory. This is fine as it basically gives the same guarantees as TCP which means even if the promise was notified before its not really guaranteed that the "remote peer" will see the buffer at all. Modifications: Ensure we release all buffers in the inbound buffer if a doClose() is called. Result: No more leaks. |
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.github | ||
all | ||
bom | ||
buffer | ||
codec | ||
codec-dns | ||
codec-haproxy | ||
codec-http | ||
codec-http2 | ||
codec-memcache | ||
codec-mqtt | ||
codec-redis | ||
codec-smtp | ||
codec-socks | ||
codec-stomp | ||
codec-xml | ||
common | ||
example | ||
handler | ||
handler-proxy | ||
license | ||
microbench | ||
resolver | ||
resolver-dns | ||
tarball | ||
testsuite | ||
testsuite-autobahn | ||
testsuite-osgi | ||
transport | ||
transport-native-epoll | ||
transport-rxtx | ||
transport-sctp | ||
transport-udt | ||
.fbprefs | ||
.gitignore | ||
.travis.yml | ||
CONTRIBUTING.md | ||
LICENSE.txt | ||
NOTICE.txt | ||
pom.xml | ||
README.md | ||
run-example.sh |
Netty Project
Netty is an asynchronous event-driven network application framework for rapid development of maintainable high performance protocol servers & clients.
Links
How to build
For the detailed information about building and developing Netty, please visit the developer guide. This page only gives very basic information.
You require the following to build Netty:
- Latest stable Oracle JDK 7
- Latest stable Apache Maven
- If you are on Linux, you need additional development packages installed on your system, because you'll build the native transport.
Note that this is build-time requirement. JDK 5 (for 3.x) or 6 (for 4.0+) is enough to run your Netty-based application.
Branches to look
Development of all versions takes place in each branch whose name is identical to <majorVersion>.<minorVersion>
. For example, the development of 3.9 and 4.0 resides in the branch '3.9' and the branch '4.0' respectively.