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mi: Remove semi-arbitrary arch awareness in packed coordinate macros 

The majority of arches end up on the right-shift path here.  I can't
think of any arch where that'd be slower than a divide, and semantically
it makes more sense to think of this as a shift operation anyway.

Signed-off-by: Adam Jackson <ajax@redhat.com>
Reviewed-by: Keith Packard <keithp@keithp.com>
Signed-off-by: Keith Packard <keithp@keithp.com>
This commit is contained in:
Adam Jackson 2014-07-22 11:05:32 -04:00 committed by Keith Packard
parent 6ddd164508
commit 29eaa61cb2
1 changed files with 0 additions and 20 deletions
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20
mi/micoord.h
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@ -32,27 +32,7 @@
/* Macros which handle a coordinate in a single register */
/*
* Most compilers will convert divisions by 65536 into shifts, if signed
* shifts exist. If your machine does arithmetic shifts and your compiler
* can't get it right, add to this line.
*/
/*
* mips compiler - what a joke - it CSEs the 65536 constant into a reg
* forcing as to use div instead of shift. Let's be explicit.
*/
#if defined(mips) || \
defined(sparc) || defined(__sparc64__) || \
defined(__alpha) || defined(__alpha__) || \
defined(__i386__) || defined(__i386) || defined(__ia64__) || \
defined(__s390x__) || defined(__s390__) || \
defined(__amd64__) || defined(amd64) || defined(__amd64)
#define GetHighWord(x) (((int) (x)) >> 16)
#else
#define GetHighWord(x) (((int) (x)) / 65536)
#endif
#if IMAGE_BYTE_ORDER == MSBFirst
#define intToCoord(i,x,y) (((x) = GetHighWord(i)), ((y) = (int) ((short) (i))))